Difference between revisions of "009C Sample Final 2, Problem 2"

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<span class="exam">(a) &nbsp;<math style="vertical-align: -14px">4-2+1-\frac{1}{2}+\frac{1}{4}-\frac{1}{8}+\cdots</math>
 
<span class="exam">(a) &nbsp;<math style="vertical-align: -14px">4-2+1-\frac{1}{2}+\frac{1}{4}-\frac{1}{8}+\cdots</math>
  
<span class="exam">(b) &nbsp;<math>\sum_{n=1}^{+\infty} \frac{1}{(2n-1)(2n+1)}</math>
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<span class="exam">(b) &nbsp;<math>\sum_{n=1}^{\infty} \frac{1}{(2n-1)(2n+1)}</math>
  
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<hr>
!Foundations: &nbsp;
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[[009C Sample Final 2, Problem 2 Solution|'''<u>Solution</u>''']]
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|'''1.''' The sum of a convergent geometric series is &nbsp; <math>\frac{a}{1-r}</math>
 
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|&nbsp; &nbsp; &nbsp; &nbsp; where &nbsp;<math style="vertical-align: 0px">r</math>&nbsp; is the ratio of the geometric series
 
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|&nbsp; &nbsp; &nbsp; &nbsp; and &nbsp;<math style="vertical-align: 0px">a</math>&nbsp; is the first term of the series.
 
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|'''2.''' The &nbsp;<math style="vertical-align: 0px">n</math>th partial sum, &nbsp;<math style="vertical-align: -3px">s_n</math>&nbsp; for a series &nbsp;<math>\sum_{n=1}^\infty a_n </math>&nbsp; is defined as
 
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&nbsp; &nbsp; &nbsp; &nbsp; <math>s_n=\sum_{i=1}^n a_i.</math>
 
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'''Solution:'''
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[[009C Sample Final 2, Problem 2 Detailed Solution|'''<u>Detailed Solution</u>''']]
  
'''(a)'''
 
  
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!Step 1: &nbsp;
 
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!Step 2: &nbsp;
 
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'''(b)'''
 
 
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!Step 1: &nbsp;
 
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!Step 2: &nbsp;
 
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!Final Answer: &nbsp;
 
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|&nbsp;&nbsp; '''(a)'''
 
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|&nbsp;&nbsp; '''(b)'''
 
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[[009C_Sample_Final_2|'''<u>Return to Sample Exam</u>''']]
 
[[009C_Sample_Final_2|'''<u>Return to Sample Exam</u>''']]

Latest revision as of 18:22, 2 December 2017

For each of the following series, find the sum if it converges. If it diverges, explain why.

(a)  

(b)  


Solution


Detailed Solution


Return to Sample Exam