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| | <span class="exam">(b) <math>\int \sin^3(x)\cos^2(x)~dx</math> | | <span class="exam">(b) <math>\int \sin^3(x)\cos^2(x)~dx</math> |
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| − | {| class="mw-collapsible mw-collapsed" style = "text-align:left;"
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| − | !Foundations:
| + | [[009B Sample Final 3, Problem 5 Solution|'''<u>Solution</u>''']] |
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| − | |'''1.''' Integration by parts tells us that | |
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| − | | <math style="vertical-align: -12px">\int u~dv=uv-\int v~du.</math>
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| − | |'''2.''' Since <math style="vertical-align: -4px">\sin^2x+\cos^2x=1,</math> we have
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| − | | <math>\sin^2x=1-\cos^2x.</math>
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| − | '''Solution:''' | + | [[009B Sample Final 3, Problem 5 Detailed Solution|'''<u>Detailed Solution</u>''']] |
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| − | '''(a)'''
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| − | !Step 1:
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| − | !Step 2:
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| − | '''(b)'''
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| − | !Step 1:
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| − | !Step 2:
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| − | '''(c)'''
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| − | !Step 1:
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| − | !Step 2:
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| − | {| class="mw-collapsible mw-collapsed" style = "text-align:left;"
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| − | !Final Answer:
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| − | |'''(a)'''
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| − | |'''(b)'''
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| − | |'''(c)'''
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| | [[009B_Sample_Final_3|'''<u>Return to Sample Exam</u>''']] | | [[009B_Sample_Final_3|'''<u>Return to Sample Exam</u>''']] |
Latest revision as of 17:45, 2 December 2017
