Difference between revisions of "009C Sample Midterm 2, Problem 4"

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<span class="exam"> Find the radius of convergence and interval of convergence of the series.
 
<span class="exam"> Find the radius of convergence and interval of convergence of the series.
  
::<span class="exam">a) <math>\sum_{n=0}^\infty n^nx^n</math>
+
<span class="exam">(a) &nbsp;<math>\sum_{n=1}^\infty n^nx^n</math>
::<span class="exam">b) <math>\sum_{n=0}^\infty \frac{(x+1)^n}{\sqrt{n}}</math>
 
  
 +
<span class="exam">(b) &nbsp;<math>\sum_{n=1}^\infty \frac{(x+1)^n}{\sqrt{n}}</math>
 +
<hr>
 +
[[009C Sample Midterm 2, Problem 4 Solution|'''<u>Solution</u>''']]
  
{| class="mw-collapsible mw-collapsed" style = "text-align:left;"
 
!Foundations: &nbsp;
 
|-
 
| Root Test
 
|-
 
| Ratio Test
 
|-
 
|
 
|}
 
  
 +
[[009C Sample Midterm 2, Problem 4 Detailed Solution|'''<u>Detailed Solution</u>''']]
  
'''Solution:'''
 
  
'''(a)'''
 
{| class="mw-collapsible mw-collapsed" style = "text-align:left;"
 
!Step 1: &nbsp;
 
|-
 
|We begin by applying the Root Test.
 
|-
 
|We have
 
|-
 
|
 
&nbsp; &nbsp; &nbsp; &nbsp; <math>\begin{array}{rcl}
 
\displaystyle{\lim_{n\rightarrow \infty} \sqrt{|a_n|}} & = & \displaystyle{\lim_{n\rightarrow \infty} \sqrt{|n^nx^n|}}\\
 
&&\\
 
& = & \displaystyle{\lim_{n\rightarrow \infty} |n^nx^n|^{\frac{1}{n}}}\\
 
&&\\
 
& = & \displaystyle{\lim_{n\rightarrow \infty} |nx|}\\
 
&&\\
 
& = & \displaystyle{n|x|}\\
 
&&\\
 
& = & \displaystyle{|x|\lim_{n\rightarrow \infty} n}\\
 
&&\\
 
& = & \displaystyle{\infty}
 
\end{array}</math>
 
|}
 
 
{| class="mw-collapsible mw-collapsed" style = "text-align:left;"
 
!Step 2: &nbsp;
 
|-
 
|This means that as long as <math>x\ne 0,</math> this series diverges.
 
|-
 
|Hence, the radius of convergence is <math>R=0</math> and
 
|-
 
|the interval of convergence is <math>\{0\}.</math>
 
|-
 
|
 
|}
 
 
'''(b)'''
 
{| class="mw-collapsible mw-collapsed" style = "text-align:left;"
 
!Step 1: &nbsp;
 
|-
 
|
 
|-
 
|
 
|-
 
|
 
|-
 
|
 
|}
 
 
{| class="mw-collapsible mw-collapsed" style = "text-align:left;"
 
!Step 2: &nbsp;
 
|-
 
|
 
|-
 
|
 
|-
 
|
 
|-
 
|
 
|}
 
 
 
{| class="mw-collapsible mw-collapsed" style = "text-align:left;"
 
!Final Answer: &nbsp;
 
|-
 
|&nbsp; &nbsp; '''(a)''' &nbsp; &nbsp; The radius of convergence is <math>R=0</math> and the interval of convergence is <math>\{0\}.</math>
 
|-
 
|&nbsp; &nbsp; '''(b)''' &nbsp; &nbsp; The radius of convergence is <math>R=1</math> and the interval fo convergence is <math>(2,4].</math>
 
|}
 
 
[[009C_Sample_Midterm_2|'''<u>Return to Sample Exam</u>''']]
 
[[009C_Sample_Midterm_2|'''<u>Return to Sample Exam</u>''']]

Latest revision as of 12:38, 12 November 2017

Find the radius of convergence and interval of convergence of the series.

(a)  

(b)  Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \sum_{n=1}^\infty \frac{(x+1)^n}{\sqrt{n}}}


Solution


Detailed Solution


Return to Sample Exam