Difference between revisions of "009C Sample Midterm 2, Problem 3"

Latest revision as of 12:35, 12 November 2017

Determine convergence or divergence:

(a) $\sum _{n=1}^{\infty }(-1)^{n}{\sqrt {\frac {1}{n}}}$

(b) $\sum _{n=1}^{\infty }(-2)^{n}{\frac {n!}{n^{n}}}$

@@ Line 1: / Line 1: @@
 <span class="exam">Determine convergence or divergence:
-::<span class="exam">a) <math>\sum_{n=1}^\infty (-1)^n \sqrt{\frac{1}{n}}</math>
+<span class="exam">(a) &nbsp;<math>\sum_{n=1}^\infty (-1)^n \sqrt{\frac{1}{n}}</math>
-::<span class="exam">b) <math>\sum_{n=1}^\infty (-2)^n \frac{n!}{n^n} </math>
+<span class="exam">(b) &nbsp;<math>\sum_{n=1}^\infty (-2)^n \frac{n!}{n^n} </math>
-{| class="mw-collapsible mw-collapsed" style = "text-align:left;"
+<hr>
-!Foundations: &nbsp;
+[[009C Sample Midterm 2, Problem 3 Solution|'''<u>Solution</u>''']]
-|-
-|
-|-
-|
-::
-|-
-|
-::
-|}
-'''Solution:'''
-'''(a)'''
+[[009C Sample Midterm 2, Problem 3 Detailed Solution|'''<u>Detailed Solution</u>''']]
-{| class="mw-collapsible mw-collapsed" style = "text-align:left;"
-!Step 1: &nbsp;
-|-
-|
-|-
-|
-|}
-{| class="mw-collapsible mw-collapsed" style = "text-align:left;"
-!Step 2: &nbsp;
-|-
-|
-|-
-|
-|}
-'''(b)'''
-{| class="mw-collapsible mw-collapsed" style = "text-align:left;"
-!Step 1: &nbsp;
-|-
-|
-|-
-|
-|-
-|
-|-
-|
-|}
-{| class="mw-collapsible mw-collapsed" style = "text-align:left;"
-!Step 2: &nbsp;
-|-
-|
-|-
-|
-|-
-|
-|-
-|
-|}
-{| class="mw-collapsible mw-collapsed" style = "text-align:left;"
-!Final Answer: &nbsp;
-|-
-|'''(a)'''
-|-
-|'''(b)'''
-|}
 [[009C_Sample_Midterm_2|'''<u>Return to Sample Exam</u>''']]