Difference between revisions of "009A Sample Midterm 1, Problem 4"

Latest revision as of 18:39, 6 November 2017

Let $y={\sqrt {3x-5}}.$

(a) Use the definition of the derivative to compute ${\frac {dy}{dx}}$ for $y={\sqrt {3x-5}}.$

(b) Find the equation of the tangent line to $y={\sqrt {3x-5}}$ at $(2,1).$

Detailed Solution with Background Information

File:9ASM1P4.jpg

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Return to Sample Exam

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-<span class="exam">Find the derivatives of the following functions. Do not simplify.
+<span class="exam"> Let &nbsp;<math style="vertical-align: -5px">y=\sqrt{3x-5}.</math>
-::<span class="exam">a) <math>f(x)=\sqrt{x}(x^2+2)</math>
+<span class="exam">(a) Use the definition of the derivative to compute &nbsp; <math>\frac{dy}{dx}</math> &nbsp; for &nbsp;<math style="vertical-align: -5px">y=\sqrt{3x-5}.</math>
-::<span class="exam">b) <math>g(x)=\frac{x+3}{x^{\frac{3}{2}}+2}</math> where <math>x>0</math>
-::<span class="exam">c) <math>h(x)=\frac{e^{-5x^3}}{\sqrt{x^2+1}}</math>
+<span class="exam">(b) Find the equation of the tangent line to &nbsp;<math style="vertical-align: -5px">y=\sqrt{3x-5}</math>&nbsp; at &nbsp;<math style="vertical-align: -5px">(2,1).</math>
+<hr>
+[[009A Sample Midterm 1, Problem 4 Detailed Solution|'''<u>Detailed Solution with Background Information</u>''']]
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-!Foundations: &nbsp;
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 [[009A_Sample_Midterm_1|'''<u>Return to Sample Exam</u>''']]

Difference between revisions of "009A Sample Midterm 1, Problem 4"

Latest revision as of 18:39, 6 November 2017

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