Difference between revisions of "009A Sample Midterm 1, Problem 3"

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<span class="exam">
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<span class="exam">Consider the following function &nbsp;<math style="vertical-align: -5px"> f:</math>
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::<math>f(x) = \left\{
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    \begin{array}{lr}
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      x^2 &  \text{if }x < 1\\
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      \sqrt{x} & \text{if }x \geq 1
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    \end{array}
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  \right.
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</math>
  
::<span class="exam">a)  
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<span class="exam">(a) Find &nbsp;<math style="vertical-align: -15px"> \lim_{x\rightarrow 1^-} f(x).</math>
::<span class="exam">b)
 
  
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<span class="exam">(b) Find &nbsp;<math style="vertical-align: -15px"> \lim_{x\rightarrow 1^+} f(x).</math>
  
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<span class="exam">(c) Find &nbsp;<math style="vertical-align: -13px"> \lim_{x\rightarrow 1} f(x).</math>
!Foundations: &nbsp;
 
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'''Solution:'''
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<span class="exam">(d) Is &nbsp;<math style="vertical-align: -5px">f</math>&nbsp; continuous at &nbsp;<math style="vertical-align: -1px">x=1?</math>&nbsp; Briefly explain.
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<hr>
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[[009A Sample Midterm 1, Problem 3 Detailed Solution|'''<u>Detailed Solution with Background Information</u>''']]
  
'''(a)'''
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[[File:9ASM1P3.jpg|600px|thumb|center]]
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'''(b)'''
 
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!Final Answer: &nbsp;
 
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[[009A_Sample_Midterm_1|'''<u>Return to Sample Exam</u>''']]
 
[[009A_Sample_Midterm_1|'''<u>Return to Sample Exam</u>''']]

Latest revision as of 18:29, 5 November 2017

Consider the following function  

(a) Find  

(b) Find  

(c) Find  

(d) Is    continuous at    Briefly explain.


Detailed Solution with Background Information

9ASM1P3.jpg


Return to Sample Exam