Difference between revisions of "031 Review Part 2, Problem 3"
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{| class="mw-collapsible mw-collapsed" style = "text-align:left;" | {| class="mw-collapsible mw-collapsed" style = "text-align:left;" | ||
!Step 1: | !Step 1: | ||
| + | |- | ||
| + | |We begin by calculating <math style="vertical-align: -1px">\text{det }B.</math> | ||
| + | |- | ||
| + | |To do this, we use cofactor expansion along the second row first and then the first column. | ||
| + | |- | ||
| + | |So, we have | ||
|- | |- | ||
| | | | ||
| + | <math>\begin{array}{rcl} | ||
| + | \displaystyle{\text{det }B} & = & \displaystyle{3(-1)^{2+2}\left|\begin{array}{ccc} | ||
| + | 1 & 3 & 4 \\ | ||
| + | 0 & 1 & 2 \\ | ||
| + | 0 & 3 & 6 | ||
| + | \end{array}\right|}\\ | ||
| + | &&\\ | ||
| + | & = & \displaystyle{3\cdot 1 \cdot (-1)^{1+1} \left|\begin{array}{cc} | ||
| + | 1 & 2 \\ | ||
| + | 3 & 6 | ||
| + | \end{array}\right|}\\ | ||
| + | &&\\ | ||
| + | & = & \displaystyle{3(6-6)}\\ | ||
| + | &&\\ | ||
| + | & = & \displaystyle{0.} | ||
| + | \end{array}</math> | ||
|} | |} | ||
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!Step 2: | !Step 2: | ||
|- | |- | ||
| − | | | + | |Since <math style="vertical-align: -4px">\text{det }B=0,</math> we have that <math style="vertical-align: 0px">B</math> is not invertible. |
|} | |} | ||
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!Step 1: | !Step 1: | ||
|- | |- | ||
| − | | | + | |If <math style="vertical-align: 0px">T</math> was onto, then <math style="vertical-align: 0px">B</math> spans <math style="vertical-align: 0px">\mathbb{R}^4.</math> |
| + | |- | ||
| + | |This would mean that <math style="vertical-align: 0px">B</math> contains 4 pivots. | ||
|} | |} | ||
| Line 53: | Line 77: | ||
!Step 2: | !Step 2: | ||
|- | |- | ||
| − | | | + | |But, if <math style="vertical-align: 0px">B</math> has 4 pivots, then <math style="vertical-align: 0px">B</math> would be invertible, which is not true. |
| + | |- | ||
| + | |Hence, <math style="vertical-align: 0px">T</math> is not onto. | ||
|} | |} | ||
| Line 60: | Line 86: | ||
!Final Answer: | !Final Answer: | ||
|- | |- | ||
| − | | '''(a)''' | + | | '''(a)''' Since <math style="vertical-align: -4px">\text{det }B=0,</math> we have that <math style="vertical-align: 0px">B</math> is not invertible. |
| + | |||
|- | |- | ||
| − | | '''(b)''' | + | | '''(b)''' No, see explaination above. |
|} | |} | ||
[[031_Review_Part_2|'''<u>Return to Sample Exam</u>''']] | [[031_Review_Part_2|'''<u>Return to Sample Exam</u>''']] | ||
Revision as of 07:03, 11 October 2017
Let
(a) Is Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle B} invertible? Explain.
(b) Define a linear transformation Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle T} by the formula Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle T(\vec{x})=B\vec{x}.} Is Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle T} onto? Explain.
| Foundations: |
|---|
| 1. A matrix Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle A} is invertible if and only if Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \text{det }A\neq 0.} |
| 2. A linear transformation Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle T} given by Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle T(\vec{x})=A\vec{x}} where Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle A} is a Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle m\times n} matrix |
|
Solution:
(a)
| Step 1: |
|---|
| We begin by calculating Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \text{det }B.} |
| To do this, we use cofactor expansion along the second row first and then the first column. |
| So, we have |
|
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \begin{array}{rcl} \displaystyle{\text{det }B} & = & \displaystyle{3(-1)^{2+2}\left|\begin{array}{ccc} 1 & 3 & 4 \\ 0 & 1 & 2 \\ 0 & 3 & 6 \end{array}\right|}\\ &&\\ & = & \displaystyle{3\cdot 1 \cdot (-1)^{1+1} \left|\begin{array}{cc} 1 & 2 \\ 3 & 6 \end{array}\right|}\\ &&\\ & = & \displaystyle{3(6-6)}\\ &&\\ & = & \displaystyle{0.} \end{array}} |
| Step 2: |
|---|
| Since Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \text{det }B=0,} we have that Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle B} is not invertible. |
(b)
| Step 1: |
|---|
| If Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle T} was onto, then Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle B} spans Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \mathbb{R}^4.} |
| This would mean that Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle B} contains 4 pivots. |
| Step 2: |
|---|
| But, if Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle B} has 4 pivots, then Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle B} would be invertible, which is not true. |
| Hence, Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle T} is not onto. |
| Final Answer: |
|---|
| (a) Since Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \text{det }B=0,} we have that Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle B} is not invertible. |
| (b) No, see explaination above. |