Difference between revisions of "031 Review Part 2, Problem 8"

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(Created page with "<span class="exam">Consider the matrix  <math style="vertical-align: -31px">A= \begin{bmatrix} 1 & -4 & 9 & -7 \\ -1 & 2 & -4 & 1 \\...")
 
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<span class="exam">Consider the matrix &nbsp;<math style="vertical-align: -31px">A=   
 
    \begin{bmatrix}
 
          1 & -4 & 9 & -7 \\
 
          -1 & 2  & -4 & 1 \\
 
          5 & -6 & 10 & 7
 
        \end{bmatrix}</math>&nbsp; and assume that it is row equivalent to the matrix
 
  
::<math>B=     
+
<span class="exam">Let &nbsp;<math style="vertical-align: -31px">A=     
 
     \begin{bmatrix}
 
     \begin{bmatrix}
           1 & 0 & -1 & 5 \\
+
           1 & 3 & 8 \\
           0 & -2 & 5 & -6 \\
+
           2 & 4 &11\\
           0 & 0 & 0 & 0
+
           1 & 2 & 5
         \end{bmatrix}.</math>    
+
         \end{bmatrix}.</math>&nbsp; Find &nbsp;<math style="vertical-align: 0px">A^{-1}</math>&nbsp; if possible.
   
 
<span class="exam">(a) List rank &nbsp;<math style="vertical-align: 0px">A</math>&nbsp; and &nbsp;<math style="vertical-align: 0px">\text{dim Nul }A.</math>
 
 
 
<span class="exam">(b) Find bases for &nbsp;<math style="vertical-align: 0px">\text{Col }A</math>&nbsp; and &nbsp;<math style="vertical-align: 0px">\text{Nul }A.</math>&nbsp; Find an example of a nonzero vector that belongs to &nbsp;<math style="vertical-align: -5px">\text{Col }A,</math>&nbsp; as well as an example of a nonzero vector that belongs to &nbsp;<math style="vertical-align: 0px">\text{Nul }A.</math>
 
  
  

Revision as of 19:16, 9 October 2017

Let    Find    if possible.


Foundations:  


Solution:

Step 1:  
Step 2:  


Final Answer:  
      

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