Difference between revisions of "8A F11 Q15"
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(Created page with "'''Question: ''' a) Find the equation of the line passing through (3, -2) and (5, 6).<br> ...") |
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|Since the slope of the line in part a) is 4, the slope of any line perpendicular to the answer in a) is <math> \frac{-1}{4}</math> | |Since the slope of the line in part a) is 4, the slope of any line perpendicular to the answer in a) is <math> \frac{-1}{4}</math> | ||
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| + | [[8AF11Final|<u>'''Return to Sample Exam</u>''']] | ||
Revision as of 16:00, 6 April 2015
Question: a) Find the equation of the line passing through (3, -2) and (5, 6).
b) Find the slope of any line perpendicular to your answer from a)
| Foundations |
|---|
| 1) We have two points on a line. How do we find the slope? |
| 2) How do you write the equation of a line, given a point on the line and the slope? |
| 3) For part b) how are the slope of a line and the slope of all perpendicular lines related? |
| Answer: |
| 1) The formula for the slope of a line through two points Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (x_1, y_1)} and Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (x_2, y_2)} is Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{y_2 - y_1}{x_2 - x_1}} . |
| 2) The point-slope form of a line is Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle y - y_1 = m (x - x_1)} where the slope of the line is m, and Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (x_1, y_1)} is a point on the line. |
| 3) If m is the slope of a line. The slope of all perpendicular lines is Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{-1}{m}} |
Solution:
| Step 1: |
|---|
| Since the slope of a line passing through two points is Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{y_2 - y_1}{x_2 - x_1} } , the slope of the line is Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{6 - (-2)}{5 - 3} = \frac{8}{2} = 4 } |
| Final Answer part a): |
|---|
| Now that we have the slope of the line and a point on the line the equation for the line is Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle y - 6 = 4(x - 5)} . Another answer is Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle y + 2 = 4(x - 3)} . These answers are the same. They just look different. |
| Final Answer part b): |
|---|
| Since the slope of the line in part a) is 4, the slope of any line perpendicular to the answer in a) is |