Difference between revisions of "009A Sample Final 2, Problem 10"

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!Step 1:    
 
!Step 1:    
 
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|First, we note that the degree of the numerator is &nbsp;<math style="vertical-align: -1px">1</math>&nbsp; and
 
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|the degree of the denominator is &nbsp;<math style="vertical-align: 0px">2.</math>&nbsp;
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!Step 2: &nbsp;
 
!Step 2: &nbsp;
 
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|Since the degree of the denominator is greater than the degree of the numerator,
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|<math style="vertical-align: -5px">f(x)</math>&nbsp; has a horizontal asymptote
 
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|&nbsp; &nbsp; &nbsp; &nbsp;<math>y=0.</math>
 
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|'''(b)'''
 
|'''(b)'''
 
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|&nbsp; &nbsp;'''(c)'''&nbsp; &nbsp; <math>y=0</math>
 
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|&nbsp; &nbsp;'''(d)'''&nbsp; &nbsp; See above
 
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[[009A_Sample_Final_2|'''<u>Return to Sample Exam</u>''']]
 
[[009A_Sample_Final_2|'''<u>Return to Sample Exam</u>''']]

Revision as of 19:19, 7 March 2017

Let

(a) Find all local maximum and local minimum values of    find all intervals where    is increasing and all intervals where    is decreasing.

(b) Find all inflection points of the function    find all intervals where the function    is concave upward and all intervals where    is concave downward.

(c) Find all horizontal asymptotes of the graph  

(d) Sketch the graph of  

Foundations:  
1.   is increasing when    and    is decreasing when  
2. The First Derivative Test tells us when we have a local maximum or local minimum.
3.   is concave up when    and    is concave down when  
4. Inflection points occur when  


Solution:

(a)

Step 1:  
Step 2:  

(b)

Step 1:  
Step 2:  

(c)

Step 1:  
First, we note that the degree of the numerator is    and
the degree of the denominator is   
Step 2:  
Since the degree of the denominator is greater than the degree of the numerator,
  has a horizontal asymptote
       
(d):  
Insert sketch


Final Answer:  
(a)
(b)
   (c)   
   (d)    See above

Return to Sample Exam