Difference between revisions of "009A Sample Final 2, Problem 3"
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!Foundations: | !Foundations: | ||
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| − | | | + | |'''1.''' '''Product Rule''' |
|- | |- | ||
| − | | | + | | <math>\frac{d}{dx}(f(x)g(x))=f(x)g'(x)+f'(x)g(x)</math> |
|- | |- | ||
| − | | | + | |'''2.''' '''Quotient Rule''' |
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| − | | | + | | <math>\frac{d}{dx}\bigg(\frac{f(x)}{g(x)}\bigg)=\frac{g(x)f'(x)-f(x)g'(x)}{(g(x))^2}</math> |
| + | |- | ||
| + | |'''3.''' '''Chain Rule''' | ||
| + | |- | ||
| + | | <math>\frac{d}{dx}(f(g(x)))=f'(g(x))g'(x)</math> | ||
|} | |} | ||
Revision as of 17:06, 7 March 2017
Compute
(a)
(b)
(c)
| Foundations: |
|---|
| 1. Product Rule |
| 2. Quotient Rule |
| 3. Chain Rule |
Solution:
(a)
| Step 1: |
|---|
| Step 2: |
|---|
(b)
| Step 1: |
|---|
| Step 2: |
|---|
(c)
| Step 1: |
|---|
| Step 2: |
|---|
| Final Answer: |
|---|
| (a) |
| (b) |
| (c) |