Difference between revisions of "009A Sample Final 3, Problem 10"

From Grad Wiki
Jump to navigation Jump to search
Line 1: Line 1:
<span class="exam">Let <math>y=\tan(x).</math>
+
<span class="exam">Let &nbsp;<math style="vertical-align: -5px">y=\tan(x).</math>
  
<span class="exam">(a) Find the differential <math>dy</math> of <math>y=\tan (x)</math> at <math>x=\frac{\pi}{4}.</math>  
+
<span class="exam">(a) Find the differential &nbsp;<math style="vertical-align: -4px">dy</math>&nbsp; of &nbsp;<math style="vertical-align: -5px">y=\tan (x)</math>&nbsp; at &nbsp;<math style="vertical-align: -15px">x=\frac{\pi}{4}.</math>  
  
<span class="exam">(b) Use differentials to find an approximate value for <math>\tan(0.885).</math> Hint: <math>\frac{\pi}{4}\approx 0.785.</math>
+
<span class="exam">(b) Use differentials to find an approximate value for &nbsp;<math style="vertical-align: -5px">\tan(0.885).</math>&nbsp; Hint: &nbsp;<math style="vertical-align: -15px">\frac{\pi}{4}\approx 0.785.</math>
  
 
{| class="mw-collapsible mw-collapsed" style = "text-align:left;"
 
{| class="mw-collapsible mw-collapsed" style = "text-align:left;"
Line 48: Line 48:
 
!Step 1: &nbsp;  
 
!Step 1: &nbsp;  
 
|-
 
|-
|
+
|First, we find &nbsp;<math style="vertical-align: -1px">dx.</math>&nbsp; We have
|-
 
|
 
|}
 
 
 
{| class="mw-collapsible mw-collapsed" style = "text-align:left;"
 
!Step 2: &nbsp;
 
|-
 
|
 
|}
 
 
 
'''(c)'''
 
 
 
{| class="mw-collapsible mw-collapsed" style = "text-align:left;"
 
!Step 1: &nbsp;  
 
 
|-
 
|-
|  
+
|&nbsp; &nbsp; &nbsp; &nbsp;<math style="vertical-align: -1px">dx=0.885-\frac{\pi}{4}\approx 0.885-0.785=0.1.</math>
 
|-
 
|-
|
+
|Then, we plug this into the differential from part (a).
 
|-
 
|-
|
+
|So, we have
|-
 
|
 
 
|-
 
|-
 
|
 
|
 +
&nbsp; &nbsp; &nbsp; &nbsp;<math>dy\,=\,2(0.1)\,=\,0.2.</math>
 
|}
 
|}
  
Line 78: Line 63:
 
!Step 2: &nbsp;
 
!Step 2: &nbsp;
 
|-
 
|-
|
+
|Now, we add the value for &nbsp;<math style="vertical-align: -4px">dy</math>&nbsp; to &nbsp;<math style="vertical-align: -16px">\tan\bigg(\frac{\pi}{4}\bigg)</math>&nbsp; to get an
 
|-
 
|-
|
+
|approximate value of &nbsp;<math style="vertical-align: -5px">\tan(0.885).</math>
 
|-
 
|-
|
+
|Hence, we have
 
|-
 
|-
 
|
 
|
 +
&nbsp; &nbsp; &nbsp; &nbsp;<math>\tan(0.885)\,\approx \, \tan\bigg(\frac{\pi}{4}\bigg)+0.2\,=\,1.2.</math>
 
|}
 
|}
  
Line 91: Line 77:
 
!Final Answer: &nbsp;  
 
!Final Answer: &nbsp;  
 
|-
 
|-
|'''(a)'''
+
|&nbsp; &nbsp; '''(a)''' &nbsp; &nbsp; <math style="vertical-align: -5px">dy=2\,dx</math>
|-
 
|'''(b)'''
 
 
|-
 
|-
|'''(c)'''
+
|&nbsp; &nbsp; '''(b)''' &nbsp; &nbsp; <math style="vertical-align: -1px">1.2</math> 
 
|}
 
|}
 
[[009A_Sample_Final_3|'''<u>Return to Sample Exam</u>''']]
 
[[009A_Sample_Final_3|'''<u>Return to Sample Exam</u>''']]

Revision as of 09:39, 7 March 2017

Let  

(a) Find the differential    of    at  

(b) Use differentials to find an approximate value for    Hint:  

Foundations:  
What is the differential    of    at  

        Since    the differential is  


Solution:

(a)

Step 1:  
First, we find the differential  
Since    we have

       

Step 2:  
Now, we plug    into the differential from Step 1.
So, we get

       

(b)

Step 1:  
First, we find    We have
       
Then, we plug this into the differential from part (a).
So, we have

       

Step 2:  
Now, we add the value for    to    to get an
approximate value of  
Hence, we have

       


Final Answer:  
    (a)    
    (b)    

Return to Sample Exam