Difference between revisions of "009C Sample Final 3, Problem 3"

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|&nbsp; &nbsp; &nbsp; &nbsp; Let &nbsp;<math>\{a_n\}</math>&nbsp; and &nbsp;<math>\{b_n\}</math>&nbsp; be positive sequences.
 
|&nbsp; &nbsp; &nbsp; &nbsp; Let &nbsp;<math>\{a_n\}</math>&nbsp; and &nbsp;<math>\{b_n\}</math>&nbsp; be positive sequences.
 
|-
 
|-
|&nbsp; &nbsp; &nbsp; &nbsp; If &nbsp;<math>\lim_{n\rightarrow \infty} \frac{a_n}{b_n}=L,</math>&nbsp; where &nbsp;<math>L</math> &nbsp; is a positive real number,
+
|&nbsp; &nbsp; &nbsp; &nbsp; If &nbsp;<math style="vertical-align: -16px">\lim_{n\rightarrow \infty} \frac{a_n}{b_n}=L,</math>&nbsp; where &nbsp;<math style="vertical-align: -1px">L</math> &nbsp;is a positive real number,
 
|-
 
|-
|&nbsp; &nbsp; &nbsp; &nbsp; then &nbsp;<math>\sum_{n=1}^\infty a_n</math>&nbsp; and &nbsp;<math>\sum_{n=1}^\infty b_n</math>&nbsp; either both converge or both diverge.
+
|&nbsp; &nbsp; &nbsp; &nbsp; then &nbsp;<math style="vertical-align: -20px">\sum_{n=1}^\infty a_n</math>&nbsp; and &nbsp;<math style="vertical-align: -20px">\sum_{n=1}^\infty b_n</math>&nbsp; either both converge or both diverge.
 
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|This means that we can use a comparison test on this series.
 
|This means that we can use a comparison test on this series.
 
|-
 
|-
|Let &nbsp;<math style="vertical-align: -14px">a_n=\frac{n^3+7n}{\sqrt{1+n^{10}}}.</math>
+
|Let &nbsp;<math style="vertical-align: -19px">a_n=\frac{n^3+7n}{\sqrt{1+n^{10}}}.</math>
 
|}
 
|}
  

Revision as of 15:48, 5 March 2017

Test if the following series converges or diverges. Give reasons and clearly state if you are using any standard test.

Foundations:  
Limit Comparison Test
        Let    and    be positive sequences.
        If    where    is a positive real number,
        then    and    either both converge or both diverge.


Solution:

Step 1:  
First, we note that
       
for all  
This means that we can use a comparison test on this series.
Let  
Step 2:  
Let  
We want to compare the series in this problem with
       
This is a  -series with  
Hence,  Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \sum_{n=1}^\infty b_n}   converges
Step 3:  
Now, we have
        Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \begin{array}{rcl} \displaystyle{\lim_{n\rightarrow \infty} \frac{a_n}{b_n}} & = & \displaystyle{\lim_{n\rightarrow \infty} \frac{(\frac{n^3+7n}{\sqrt{1+n^{10}}})}{(\frac{1}{n^2})}}\\ &&\\ & = & \displaystyle{\lim_{n\rightarrow \infty} \frac{n^5+7n^3}{\sqrt{1+n^{10}}}}\\ &&\\ & = & \displaystyle{\lim_{n\rightarrow \infty} \frac{n^5+7n^3}{\sqrt{1+n^{10}}} \bigg(\frac{\frac{1}{n^5}}{\frac{1}{n^5}}\bigg)}\\ &&\\ & = & \displaystyle{\lim_{n\rightarrow \infty} \frac{1+\frac{7}{n^4}}{\sqrt{\frac{1}{n^{10}}+1}}}\\ &&\\ & = & \displaystyle{1.} \end{array}}
Therefore, the series
        Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \sum_{n=1}^{\infty} \frac{n^3+7n}{\sqrt{1+n^{10}}}}
converges by the Limit Comparison Test.


Final Answer:  
        converges

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