Difference between revisions of "009C Sample Final 2, Problem 9"

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!Foundations:    
 
!Foundations:    
 
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|How do you calculate &nbsp; <math style="vertical-align: -5px">y'</math> &nbsp; for a polar curve &nbsp;<math style="vertical-align: -5px">r=f(\theta)?</math>
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&nbsp; &nbsp; &nbsp; &nbsp;Since &nbsp; <math style="vertical-align: -5px">x=r\cos(\theta),~y=r\sin(\theta),</math>&nbsp; we have
 
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&nbsp; &nbsp; &nbsp; &nbsp;<math>y'=\frac{dy}{dx}=\frac{\frac{dr}{d\theta}\sin\theta+r\cos\theta}{\frac{dr}{d\theta}\cos\theta-r\sin\theta}.</math>
 
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'''Solution:'''
 
'''Solution:'''
 
'''(a)'''
 
  
 
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{| class="mw-collapsible mw-collapsed" style = "text-align:left;"
!Step 1: &nbsp;  
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!(a) &nbsp;  
 
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|Insert sketch of graph
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{| class="mw-collapsible mw-collapsed" style = "text-align:left;"
 
!Step 2: &nbsp;
 
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Revision as of 21:38, 4 March 2017

A curve is given in polar coordinates by

(a) Sketch the curve.

(b) Compute  

(c) Compute  

Foundations:  
How do you calculate     for a polar curve  

       Since     we have

       


Solution:

(a)  
Insert sketch of graph

(b)

Step 1:  
Step 2:  

(c)

Step 1:  
Step 2:  


Final Answer:  
   (a)
   (b)
   (c)

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