Difference between revisions of "009C Sample Final 2, Problem 3"
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!Step 1: | !Step 1: | ||
|- | |- | ||
− | | | + | |For |
|- | |- | ||
− | | | + | | <math>\sum_{n=1}^\infty (-1)^n\frac{1}{n+1},</math> |
|- | |- | ||
− | | | + | |we notice that this series is alternating. |
+ | |- | ||
+ | |Let <math style="vertical-align: -16px"> b_n=\frac{1}{n+1}.</math> | ||
+ | |- | ||
+ | |The sequence <math style="vertical-align: -5px">\{b_n\}</math> is decreasing since | ||
+ | |- | ||
+ | | <math>\frac{1}{n+2}<\frac{1}{n+1}</math> | ||
+ | |- | ||
+ | |for all <math style="vertical-align: -3px">n\ge 0.</math> | ||
|} | |} | ||
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!Step 2: | !Step 2: | ||
|- | |- | ||
− | | | + | |Also, |
+ | |- | ||
+ | | <math>\lim_{n\rightarrow \infty}b_n=\lim_{n\rightarrow \infty}\frac{1}{n+1}=0.</math> | ||
+ | |- | ||
+ | |Therefore, the series <math>\sum_{n=1}^\infty (-1)^n\frac{1}{n+1}</math> converges | ||
|- | |- | ||
− | | | + | |by the Alternating Series Test. |
|} | |} | ||
Line 68: | Line 80: | ||
| '''(a)''' | | '''(a)''' | ||
|- | |- | ||
− | | '''(b)''' | + | | '''(b)''' converges |
|} | |} | ||
[[009C_Sample_Final_2|'''<u>Return to Sample Exam</u>''']] | [[009C_Sample_Final_2|'''<u>Return to Sample Exam</u>''']] |
Revision as of 20:40, 4 March 2017
Determine if the following series converges or diverges. Please give your reason(s).
(a)
(b)
Foundations: |
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Solution:
(a)
Step 1: |
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Step 2: |
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(b)
Step 1: |
---|
For |
we notice that this series is alternating. |
Let |
The sequence is decreasing since |
for all |
Step 2: |
---|
Also, |
Therefore, the series converges |
by the Alternating Series Test. |
Final Answer: |
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(a) |
(b) converges |