Difference between revisions of "009B Sample Final 2, Problem 5"
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!Foundations: | !Foundations: | ||
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− | | | + | |'''1.''' The formula for the length <math style="vertical-align: 0px">L</math> of a curve <math style="vertical-align: -5px">y=f(x)</math> where <math style="vertical-align: -3px">a\leq x \leq b</math> is |
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+ | <math>L=\int_a^b \sqrt{1+\bigg(\frac{dy}{dx}\bigg)^2}~dx.</math> | ||
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− | | | + | |'''2.''' The surface area <math style="vertical-align: 0px">S</math> of a function <math style="vertical-align: -5px">y=f(x)</math> rotated about the <math style="vertical-align: -4px">y</math>-axis is given by |
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+ | <math style="vertical-align: -13px">S=\int 2\pi x\,ds,</math> where <math style="vertical-align: -18px">ds=\sqrt{1+\bigg(\frac{dy}{dx}\bigg)^2}.</math> | ||
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Revision as of 14:28, 4 March 2017
(a) Find the area of the surface obtained by rotating the arc of the curve
between and about the -axis.
(b) Find the length of the arc
between the points and
Foundations: |
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1. The formula for the length of a curve where is |
|
2. The surface area of a function rotated about the -axis is given by |
where |
Solution:
(a)
Step 1: |
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Step 2: |
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(b)
Step 1: |
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Step 2: |
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Final Answer: |
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(a) |
(b) |