Difference between revisions of "009B Sample Final 3, Problem 6"
		
		
		
		
		
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| Kayla Murray (talk | contribs) | Kayla Murray (talk | contribs)  | ||
| Line 25: | Line 25: | ||
| |First, we factor the denominator to get | |First, we factor the denominator to get | ||
| |- | |- | ||
| − | |<math>\int \frac{3x-1}{2x^2-x}~dx=\int \frac{3x-1}{x(2x-1)}.</math> | + | |       <math>\int \frac{3x-1}{2x^2-x}~dx=\int \frac{3x-1}{x(2x-1)}.</math> | 
| |- | |- | ||
| |We use the method of partial fraction decomposition. | |We use the method of partial fraction decomposition. | ||
| Line 31: | Line 31: | ||
| |We let   | |We let   | ||
| |- | |- | ||
| − | |<math>\frac{3x-1}{x(2x-1)}=\frac{A}{x}+\frac{B}{2x-1}.</math> | + | |       <math>\frac{3x-1}{x(2x-1)}=\frac{A}{x}+\frac{B}{2x-1}.</math> | 
| |} | |} | ||
Revision as of 13:46, 2 March 2017
Find the following integrals
(a)
(b)
| Foundations: | 
|---|
| Through partial fraction decomposition, we can write the fraction | 
| for some constants | 
Solution:
(a)
| Step 1: | 
|---|
| First, we factor the denominator to get | 
| We use the method of partial fraction decomposition. | 
| We let | 
| Step 2: | 
|---|
(b)
| Step 1: | 
|---|
| Step 2: | 
|---|
| Final Answer: | 
|---|
| (a) | 
| (b) |