Difference between revisions of "009A Sample Midterm 1, Problem 2"

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!Foundations:    
 
!Foundations:    
 
|-
 
|-
|'''1.''' If <math style="vertical-align: -15px">\lim_{x\rightarrow a^-} f(x)=\lim_{x\rightarrow a^+} f(x)=c,</math>
+
|'''1.''' If &nbsp;<math style="vertical-align: -15px">\lim_{x\rightarrow a^-} f(x)=\lim_{x\rightarrow a^+} f(x)=c,</math>
 
|-
 
|-
|&nbsp; &nbsp; &nbsp; &nbsp; then <math style="vertical-align: -12px">\lim_{x\rightarrow a} f(x)=c.</math>
+
|&nbsp; &nbsp; &nbsp; &nbsp; then &nbsp;<math style="vertical-align: -12px">\lim_{x\rightarrow a} f(x)=c.</math>
 
|-
 
|-
|'''2.''' '''Definition of continuous'''
+
|'''2.''' &nbsp;<math style="vertical-align: -5px">f(x)</math>&nbsp; is continuous at &nbsp;<math style="vertical-align: 0px">x=a</math>&nbsp; if  
|-
 
|&nbsp; &nbsp; &nbsp; &nbsp; <math style="vertical-align: -5px">f(x)</math> is continuous at <math style="vertical-align: 0px">x=a</math> if  
 
 
|-
 
|-
 
|&nbsp; &nbsp; &nbsp; &nbsp; <math style="vertical-align: -14px">\lim_{x\rightarrow a^+}f(x)=\lim_{x\rightarrow a^-}f(x)=f(a).</math>
 
|&nbsp; &nbsp; &nbsp; &nbsp; <math style="vertical-align: -14px">\lim_{x\rightarrow a^+}f(x)=\lim_{x\rightarrow a^-}f(x)=f(a).</math>
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|Notice that we are calculating a left hand limit.
 
|Notice that we are calculating a left hand limit.
 
|-
 
|-
|Thus, we are looking at values of <math style="vertical-align: 0px">x</math> that are smaller than <math style="vertical-align: -2px">1.</math>
+
|Thus, we are looking at values of &nbsp;<math style="vertical-align: 0px">x</math>&nbsp; that are smaller than &nbsp;<math style="vertical-align: -2px">1.</math>
 
|-
 
|-
|Using the definition of <math style="vertical-align: -5px">f(x)</math>, we have
+
|Using the definition of &nbsp;<math style="vertical-align: -5px">f(x),</math>&nbsp; we have
 
|-
 
|-
 
|&nbsp; &nbsp; &nbsp; &nbsp; <math>\lim_{x\rightarrow 1^-} f(x)=\lim_{x\rightarrow 1^-} x^2.</math>  
 
|&nbsp; &nbsp; &nbsp; &nbsp; <math>\lim_{x\rightarrow 1^-} f(x)=\lim_{x\rightarrow 1^-} x^2.</math>  
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|Notice that we are calculating a right hand limit.
 
|Notice that we are calculating a right hand limit.
 
|-
 
|-
|Thus, we are looking at values of <math style="vertical-align: 0px">x</math> that are bigger than <math style="vertical-align: -2px">1.</math>
+
|Thus, we are looking at values of &nbsp;<math style="vertical-align: 0px">x</math>&nbsp; that are bigger than &nbsp;<math style="vertical-align: -2px">1.</math>
 
|-
 
|-
|Using the definition of <math style="vertical-align: -5px">f(x)</math>, we have
+
|Using the definition of &nbsp;<math style="vertical-align: -5px">f(x),</math>&nbsp; we have
 
|-
 
|-
 
|&nbsp; &nbsp; &nbsp; &nbsp; <math>\lim_{x\rightarrow 1^+} f(x)=\lim_{x\rightarrow 1^+} \sqrt{x}.</math>  
 
|&nbsp; &nbsp; &nbsp; &nbsp; <math>\lim_{x\rightarrow 1^+} f(x)=\lim_{x\rightarrow 1^+} \sqrt{x}.</math>  
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|&nbsp; &nbsp; &nbsp; &nbsp; <math>\lim_{x\rightarrow 1}f(x)=f(1),</math>
 
|&nbsp; &nbsp; &nbsp; &nbsp; <math>\lim_{x\rightarrow 1}f(x)=f(1),</math>
 
|-
 
|-
|<math style="vertical-align: -5px">f(x)</math> is continuous at <math style="vertical-align: -1px">x=1.</math>
+
|<math style="vertical-align: -5px">f(x)</math> &nbsp;is continuous at &nbsp;<math style="vertical-align: -1px">x=1.</math>
 
|-
 
|-
 
|
 
|

Revision as of 16:46, 26 February 2017

Consider the following function  

(a) Find  

(b) Find  

(c) Find  

(d) Is    continuous at    Briefly explain.


Foundations:  
1. If  
        then  
2.    is continuous at    if
       


Solution:

(a)

Step 1:  
Notice that we are calculating a left hand limit.
Thus, we are looking at values of    that are smaller than  
Using the definition of    we have
       
Step 2:  
Now, we have

       

(b)

Step 1:  
Notice that we are calculating a right hand limit.
Thus, we are looking at values of    that are bigger than  
Using the definition of  Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f(x),}   we have
        Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \lim_{x\rightarrow 1^+} f(x)=\lim_{x\rightarrow 1^+} \sqrt{x}.}
Step 2:  
Now, we have

        Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \begin{array}{rcl} \displaystyle{\lim_{x\rightarrow 1^+} f(x)} & = & \displaystyle{\lim_{x\rightarrow 1^+} \sqrt{x}}\\ &&\\ & = & \displaystyle{\lim_{x\rightarrow 1} \sqrt{x}}\\ &&\\ & = & \displaystyle{\sqrt{1}}\\ &&\\ & = & \displaystyle{1.}\\ \end{array}}

(c)

Step 1:  
From (a) and (b), we have
       
and
        Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \lim_{x\rightarrow 1^+}f(x)=1.}
Step 2:  
Since
        Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \lim_{x\rightarrow 1^-}f(x)=\lim_{x\rightarrow 1^+}f(x)=1,}
we have
        Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \lim_{x\rightarrow 1}f(x)=1.}

(d)

Step 1:  
From (c), we have
        Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \lim_{x\rightarrow 1}f(x)=1.}
Also,
        Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f(1)=\sqrt{1}=1.}
Step 2:  
Since
        Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \lim_{x\rightarrow 1}f(x)=f(1),}
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f(x)}  is continuous at  Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x=1.}


Final Answer:  
    (a)     Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 1}
    (b)     Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 1}
    (c)     Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 1}
    (d)     Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f(x)} is continuous at Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x=1} since Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \lim_{x\rightarrow 1}f(x)=f(1).}

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