Difference between revisions of "009A Sample Midterm 2, Problem 2"
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|'''Intermediate Value Theorem''' | |'''Intermediate Value Theorem''' | ||
Revision as of 12:00, 26 February 2017
The function is a polynomial and therefore continuous everywhere.
(a) State the Intermediate Value Theorem.
(b) Use the Intermediate Value Theorem to show that has a zero in the interval
| Foundations: |
|---|
| What is a zero of the function |
| A zero is a value such that |
Solution:
| (a) |
|---|
| Intermediate Value Theorem |
| If is continuous on a closed interval |
| and is any number between and |
|
then there is at least one number in the closed interval such that |
(b)
| Step 1: |
|---|
| First, is continuous on the interval since is continuous everywhere. |
| Also, |
|
|
| and
. |
| Step 2: |
|---|
| Since is between and |
| the Intermediate Value Theorem tells us that there is at least one number |
| such that |
| This means that has a zero in the interval |
| Final Answer: |
|---|
| (a) See solution above. |
| (b) See solution above. |