Difference between revisions of "009C Sample Final 2, Problem 10"

Revision as of 10:33, 18 February 2017

Find the length of the curve given by

x=t^{2}

y=t^{3}

0\leq t\leq 2

Solution:

(a)

Step 2:

(b)

Step 2:

Final Answer:
(a)
(b)

@@ Line 1: / Line 1: @@
-<span class="exam">Compute
+<span class="exam">Find the length of the curve given by
+::::<span class="exam"><math>x=t^2</math>
-::<span class="exam">a) <math style="vertical-align: -12px">\lim_{n\rightarrow \infty} \frac{3-2n^2}{5n^2+n+1}</math>
+::::<span class="exam"><math>y=t^3</math>
+::::<span class="exam"><math>0\leq t \leq 2</math>
-::<span class="exam">b) <math style="vertical-align: -12px">\lim_{n\rightarrow \infty} \frac{\ln n}{\ln 3n}</math>
 {| class="mw-collapsible mw-collapsed" style = "text-align:left;"