Difference between revisions of "009A Sample Midterm 3, Problem 6"
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!Step 1: | !Step 1: | ||
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| − | | | + | |First, using the Chain Rule, we have |
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| − | | | + | | <math>h'(x)=8(x+\cos^2(x))^7(x+\cos^2(x))'.</math> |
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!Step 2: | !Step 2: | ||
|- | |- | ||
| − | | | + | |Now, using the Chain Rule again we get |
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| + | <math>\begin{array}{rcl} | ||
| + | \displaystyle{h'(x)} & = & \displaystyle{8(x+\cos^2(x))^7(x+\cos^2(x))'}\\ | ||
| + | &&\\ | ||
| + | & = & \displaystyle{8(x+\cos^2(x))^7(1+2\cos(x)(\cos(x))')}\\ | ||
| + | &&\\ | ||
| + | & = & \displaystyle{8(x+\cos^2(x))^7(1-2\cos(x)\sin(x)).} | ||
| + | \end{array}</math> | ||
|} | |} | ||
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|'''(b)''' | |'''(b)''' | ||
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| − | |'''(c)''' | + | | '''(c)''' <math>8(x+\cos^2(x))^7(1-2\cos(x)\sin(x))</math> |
|} | |} | ||
[[009A_Sample_Midterm_3|'''<u>Return to Sample Exam</u>''']] | [[009A_Sample_Midterm_3|'''<u>Return to Sample Exam</u>''']] | ||
Revision as of 15:51, 17 February 2017
Find the derivatives of the following functions. Do not simplify.
- a)
- b)
- c)
| Foundations: |
|---|
| 1. Chain Rule |
| 2. Quotient Rule |
Solution:
(a)
| Step 1: |
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| Step 2: |
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(b)
| Step 1: |
|---|
| Step 2: |
|---|
(c)
| Step 1: |
|---|
| First, using the Chain Rule, we have |
| Step 2: |
|---|
| Now, using the Chain Rule again we get |
|
|
| Final Answer: |
|---|
| (a) |
| (b) |
| (c) |