Difference between revisions of "009A Sample Midterm 3, Problem 3"
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{| class="mw-collapsible mw-collapsed" style = "text-align:left;" | {| class="mw-collapsible mw-collapsed" style = "text-align:left;" | ||
!Step 1: | !Step 1: | ||
| + | |- | ||
| + | |Let <math>f(x)=3\sqrt{-2x+5}.</math> | ||
| + | |- | ||
| + | |Using the limit definition of the derivative, we have | ||
|- | |- | ||
| | | | ||
| + | <math>\begin{array}{rcl} | ||
| + | \displaystyle{f'(x)} & = & \displaystyle{\lim_{h\rightarrow 0} \frac{f(x+h)-f(x)}{h}}\\ | ||
| + | &&\\ | ||
| + | & = & \displaystyle{\lim_{h\rightarrow 0} \frac{3\sqrt{-2(x+h)+5}-3\sqrt{-2x+5}}{h}}\\ | ||
| + | &&\\ | ||
| + | & = & \displaystyle{\lim_{h\rightarrow 0} \frac{3\sqrt{-2x+-2h+5}-3\sqrt{-2x+5}}{h}.} | ||
| + | \end{array}</math> | ||
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Revision as of 15:28, 17 February 2017
Use the definition of the derivative to compute for
| Foundations: |
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| Limit Definition of Derivative |
Solution:
| Step 1: |
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| Let |
| Using the limit definition of the derivative, we have |
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| Step 2: |
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| Final Answer: |
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