Difference between revisions of "009A Sample Midterm 3, Problem 2"
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Kayla Murray (talk | contribs) |
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!Step 1: | !Step 1: | ||
|- | |- | ||
| − | | | + | |First, we need to find the time when the object hits the ground. |
| + | |- | ||
| + | |This corresponds to <math>s(t)=0.</math> | ||
| + | |- | ||
| + | |This give us the equation | ||
| + | |- | ||
| + | | <math>-4.9t^2+200=0.</math> | ||
| + | |- | ||
| + | |When we solve for <math>t,</math> we get | ||
| + | |- | ||
| + | | <math>t^2=\frac{200}{4.9}.</math> | ||
|- | |- | ||
| − | | | + | |Hence, <math>t=\pm \sqrt{\frac{200}{4.9}}.</math> |
|- | |- | ||
| − | | | + | |Since <math>t</math> represents time, it does not make sense for <math>t</math> to be negative. |
|- | |- | ||
| − | | | + | |Therefore, the object hits the ground at <math>t=\sqrt{\frac{200}{4.9}}.</math> |
|} | |} | ||
| Line 72: | Line 82: | ||
!Step 2: | !Step 2: | ||
|- | |- | ||
| − | | | + | |Now, we need the equation for the velocity of the object. |
| + | |- | ||
| + | |We have <math>v(t)=s'(t)</math> where <math>v(t)</math> is the velocity function of the object. | ||
| + | |- | ||
| + | |Hence, | ||
|- | |- | ||
| | | | ||
| + | <math>\begin{array}{rcl} | ||
| + | \displaystyle{v(t)} & = & \displaystyle{s'(t)}\\ | ||
| + | &&\\ | ||
| + | & = & \displaystyle{-9.8t.} | ||
| + | \end{array}</math> | ||
|- | |- | ||
| − | | | + | |Therefore, the velocity of the object when it hits the ground is |
|- | |- | ||
| − | | | + | | <math>-9.8\sqrt{\frac{200}{4.9}}\text{ meters/second}.</math> |
|} | |} | ||
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| '''(a)''' <math>6(-4.9) \text{ meters/second}</math> | | '''(a)''' <math>6(-4.9) \text{ meters/second}</math> | ||
|- | |- | ||
| − | |'''(b)''' | + | | '''(b)''' <math>-9.8\sqrt{\frac{200}{4.9}}\text{ meters/second}</math> |
|} | |} | ||
[[009A_Sample_Midterm_3|'''<u>Return to Sample Exam</u>''']] | [[009A_Sample_Midterm_3|'''<u>Return to Sample Exam</u>''']] | ||
Revision as of 14:19, 17 February 2017
The position function Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle s(t)=-4.9t^2+200} gives the height (in meters) of an object that has fallen from a height of 200 meters. The velocity at time Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle t=a} seconds is given by:
- Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \lim_{t\rightarrow a} \frac{s(t)-s(a)}{t-a}}
- a) Find the velocity of the object when Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle t=3}
- b) At what velocity will the object impact the ground?
| Foundations: |
|---|
Solution:
(a)
| Step 1: |
|---|
| Let Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle v(t)} be the velocity of the object at time Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle t.} |
| Then, we have |
| Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \begin{array}{rcl} \displaystyle{v(3)} & = & \displaystyle{\lim_{t\rightarrow 3} \frac{s(t)-s(3)}{t-3}}\\ &&\\ & = & \displaystyle{\lim_{t\rightarrow 3} \frac{-4.9t^2+200-(-4.9(9)+200)}{t-3}}\\ &&\\ & = & \displaystyle{\lim_{t\rightarrow 3} \frac{-4.9t^2+44.1}{t-3}.} \end{array}} |
| Step 2: |
|---|
| Now, we factor the numerator to get |
|
|
(b)
| Step 1: |
|---|
| First, we need to find the time when the object hits the ground. |
| This corresponds to Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle s(t)=0.} |
| This give us the equation |
| Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle -4.9t^2+200=0.} |
| When we solve for Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle t,} we get |
| Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle t^2=\frac{200}{4.9}.} |
| Hence, Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle t=\pm \sqrt{\frac{200}{4.9}}.} |
| Since Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle t} represents time, it does not make sense for Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle t} to be negative. |
| Therefore, the object hits the ground at Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle t=\sqrt{\frac{200}{4.9}}.} |
| Step 2: |
|---|
| Now, we need the equation for the velocity of the object. |
| We have Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle v(t)=s'(t)} where Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle v(t)} is the velocity function of the object. |
| Hence, |
|
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \begin{array}{rcl} \displaystyle{v(t)} & = & \displaystyle{s'(t)}\\ &&\\ & = & \displaystyle{-9.8t.} \end{array}} |
| Therefore, the velocity of the object when it hits the ground is |
| Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle -9.8\sqrt{\frac{200}{4.9}}\text{ meters/second}.} |
| Final Answer: |
|---|
| (a) Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 6(-4.9) \text{ meters/second}} |
| (b) Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle -9.8\sqrt{\frac{200}{4.9}}\text{ meters/second}} |