Difference between revisions of "009A Sample Midterm 2, Problem 2"
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| − | | | + | |'''Intermediate Value Theorem''' |
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| − | | | + | | If <math style="vertical-align: -5px">f(x)</math>  is continuous on a closed interval <math style="vertical-align: -5px">[a,b]</math> |
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| − | | | + | | and <math style="vertical-align: 0px">c</math> is any number between <math style="vertical-align: -5px">f(a)</math>  and <math style="vertical-align: -5px">f(b)</math>, |
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| + | then there is at least one number <math style="vertical-align: 0px">x</math> in the closed interval such that <math style="vertical-align: -5px">f(x)=c.</math> | ||
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Revision as of 12:37, 17 February 2017
The function is a polynomial and therefore continuous everywhere.
- a) State the Intermediate Value Theorem.
- b) Use the Intermediate Value Theorem to show that has a zero in the interval
| Foundations: |
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Solution:
(a)
| Step 1: |
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| Intermediate Value Theorem |
| If is continuous on a closed interval |
| and is any number between and , |
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then there is at least one number in the closed interval such that |
(b)
| Step 1: |
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| Step 2: |
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| Final Answer: |
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| (a) |
| (b) |