Difference between revisions of "009C Sample Midterm 2, Problem 3"
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| <math>\lim_{n\rightarrow \infty}b_n=\lim_{n\rightarrow \infty}\frac{1}{\sqrt{n}}=0.</math> | | <math>\lim_{n\rightarrow \infty}b_n=\lim_{n\rightarrow \infty}\frac{1}{\sqrt{n}}=0.</math> | ||
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− | |Therefore, the series <math>\sum_{n=1}^\infty \frac{(-1)^n}{\sqrt{n | + | |Therefore, the series <math>\sum_{n=1}^\infty \frac{(-1)^n}{\sqrt{n}}</math> converges by the Alternating Series Test. |
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Revision as of 12:05, 13 February 2017
Determine convergence or divergence:
- a)
- b)
Foundations: |
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Alternating Series Test |
Ratio Test |
Solution:
(a)
Step 1: |
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First, we have |
Step 2: |
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We notice that the series is alternating. |
Let |
The sequence is decreasing since |
for all |
Also, |
Therefore, the series converges by the Alternating Series Test. |
(b)
Step 1: |
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Step 2: |
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Final Answer: |
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(a) converges |
(b) |