Difference between revisions of "009A Sample Final 1, Problem 2"
Kayla Murray (talk | contribs) |
Kayla Murray (talk | contribs) |
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!Step 1: | !Step 1: | ||
|- | |- | ||
| − | | | + | |We first calculate <math>\lim_{x\rightarrow 3^+}f(x)</math>. We have |
|- | |- | ||
| | | | ||
| + | ::<math>\begin{array}{rcl} | ||
| + | \displaystyle{\lim_{x\rightarrow 3^+}f(x)} & = & \displaystyle{\lim_{x\rightarrow 3} 4\sqrt{x+1}}\\ | ||
| + | &&\\ | ||
| + | & = & \displaystyle{4\sqrt{3+1}}\\ | ||
| + | &&\\ | ||
| + | & = & \displaystyle{8} | ||
| + | \end{array}</math> | ||
| + | |} | ||
| + | |||
| + | {| class="mw-collapsible mw-collapsed" style = "text-align:left;" | ||
| + | !Step 2: | ||
|- | |- | ||
| − | | | + | |Now, we calculate <math>\lim_{x\rightarrow 3^-}f(x)</math>. We have |
|- | |- | ||
| | | | ||
| + | ::<math>\begin{array}{rcl} | ||
| + | \displaystyle{\lim_{x\rightarrow 3^-}f(x)} & = & \displaystyle{\lim_{x\rightarrow 3} x+5}\\ | ||
| + | &&\\ | ||
| + | & = & \displaystyle{3+5}\\ | ||
| + | &&\\ | ||
| + | & = & \displaystyle{8} | ||
| + | \end{array}</math> | ||
|} | |} | ||
{| class="mw-collapsible mw-collapsed" style = "text-align:left;" | {| class="mw-collapsible mw-collapsed" style = "text-align:left;" | ||
| − | !Step | + | !Step 3: |
|- | |- | ||
| − | | | + | |Now, we calculate <math>f(3)</math>. We have |
|- | |- | ||
| − | | | + | |<math>f(3)=4\sqrt{3+1}=8</math>. |
|- | |- | ||
| − | | | + | |Since <math>\lim_{x\rightarrow 3^+}f(x)=\lim_{x\rightarrow 3^-}f(x)=f(3)</math>, <math>f(x)</math> is continuous. |
|} | |} | ||
| Line 73: | Line 91: | ||
!Final Answer: | !Final Answer: | ||
|- | |- | ||
| − | |'''(a)''' | + | |'''(a)''' Since <math>\lim_{x\rightarrow 3^+}f(x)=\lim_{x\rightarrow 3^-}f(x)=f(3)</math>, <math>f(x)</math> is continuous. |
|- | |- | ||
|'''(b)''' | |'''(b)''' | ||
|} | |} | ||
[[009A_Sample_Final_1|'''<u>Return to Sample Exam</u>''']] | [[009A_Sample_Final_1|'''<u>Return to Sample Exam</u>''']] | ||
Revision as of 11:05, 15 February 2016
Consider the following piecewise defined function:
- Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f(x) = \left\{ \begin{array}{lr} x+5 & \text{if }x < 3\\ 4\sqrt{x+1} & \text{if }x \geq 3 \end{array} \right. }
a) Show that Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f(x)} is continuous at Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x=3} .
b) Using the limit definition of the derivative, and computing the limits from both sides, show that Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f(x)} is differentiable at Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x=3} .
| Foundations: |
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Solution:
(a)
| Step 1: |
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| We first calculate Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \lim_{x\rightarrow 3^+}f(x)} . We have |
|
| Step 2: |
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| Now, we calculate . We have |
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| Step 3: |
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| Now, we calculate Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f(3)} . We have |
| Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f(3)=4\sqrt{3+1}=8} . |
| Since Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \lim_{x\rightarrow 3^+}f(x)=\lim_{x\rightarrow 3^-}f(x)=f(3)} , Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f(x)} is continuous. |
(b)
| Step 1: |
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| Step 2: |
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| Step 3: |
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| Final Answer: |
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| (a) Since Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \lim_{x\rightarrow 3^+}f(x)=\lim_{x\rightarrow 3^-}f(x)=f(3)} , Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f(x)} is continuous. |
| (b) |