Difference between revisions of "009A Sample Final 1, Problem 8"
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Kayla Murray (talk | contribs) |
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!Step 1: | !Step 1: | ||
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− | | | + | |First, we find the differential <math>dy</math>. |
− | |||
− | |||
|- | |- | ||
− | | | + | |Since <math>y=x^3</math>, we have |
|- | |- | ||
− | | | + | |<math>dy=3x^2dx</math>. |
|} | |} | ||
Line 32: | Line 30: | ||
!Step 2: | !Step 2: | ||
|- | |- | ||
− | | | + | |Now, we plug in <math>x=2</math> into the differential from Step 1. |
|- | |- | ||
− | | | + | |So, we get |
|- | |- | ||
− | | | + | |<math>dy=3(2)^2dx=12dx</math>. |
|} | |} | ||
Line 68: | Line 66: | ||
!Final Answer: | !Final Answer: | ||
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− | |'''(a)''' | + | |'''(a)''' <math>dy=12dx</math> |
|- | |- | ||
|'''(b)''' | |'''(b)''' | ||
|} | |} | ||
[[009A_Sample_Final_1|'''<u>Return to Sample Exam</u>''']] | [[009A_Sample_Final_1|'''<u>Return to Sample Exam</u>''']] |
Revision as of 10:04, 15 February 2016
Let
a) Find the differential of at .
b) Use differentials to find an approximate value for .
Foundations: |
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Solution:
(a)
Step 1: |
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First, we find the differential . |
Since , we have |
. |
Step 2: |
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Now, we plug in into the differential from Step 1. |
So, we get |
. |
(b)
Step 1: |
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Step 2: |
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Step 3: |
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Final Answer: |
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(a) |
(b) |