Difference between revisions of "009B Sample Final 1, Problem 4"
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!Step 2: | !Step 2: | ||
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− | | | + | |Now, for the one remaining integral, we use <math>u</math>-substitution. |
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− | | | + | |Let <math>u=e^x</math>. Then, <math>du=e^xdx</math>. So, we have |
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− | | | + | |<math>\int e^x(x+\sin(e^x))~dx=xe^x-e^x+\int \sin(u)~du=xe^x-e^x-\cos(u)+C=xe^x-e^x-\cos(e^x)+C</math>. |
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!Final Answer: | !Final Answer: | ||
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− | |'''(a)''' | + | |'''(a)''' <math>xe^x-e^x-\cos(e^x)+C</math> |
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|'''(b)''' | |'''(b)''' |
Revision as of 08:36, 2 February 2016
Compute the following integrals.
a)
b)
c)
Foundations: |
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Review -substitution and |
Integration by parts |
Solution:
(a)
Step 1: |
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We first distribute to get . |
Now, for the first integral on the right hand side of the last equation, we use integration by parts. |
Let and . Then, and . So, we have |
Step 2: |
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Now, for the one remaining integral, we use -substitution. |
Let . Then, . So, we have |
. |
(b)
Step 1: |
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Step 2: |
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Step 3: |
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(c)
Step 1: |
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Step 2: |
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Final Answer: |
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(a) |
(b) |
(c) |