|
|
| Line 2: |
Line 2: |
| | ::::::<math>r=1+\sin\theta</math> | | ::::::<math>r=1+\sin\theta</math> |
| | | | |
| − | ::<span class="exam">a) Sketch the curve.
| + | <span class="exam">a) Sketch the curve. |
| − | ::<span class="exam">b) Compute <math>y'=\frac{dy}{dx}</math>.
| + | |
| − | ::<span class="exam">c) Compute <math>y''=\frac{d^2y}{dx^2}</math>.
| + | <span class="exam">b) Compute <math>y'=\frac{dy}{dx}</math>. |
| | + | |
| | + | <span class="exam">c) Compute <math>y''=\frac{d^2y}{dx^2}</math>. |
| | | | |
| | {| class="mw-collapsible mw-collapsed" style = "text-align:left;" | | {| class="mw-collapsible mw-collapsed" style = "text-align:left;" |
Revision as of 22:03, 1 February 2016
A curve is given in polar coordinates by

a) Sketch the curve.
b) Compute
.
c) Compute
.
Solution:
(a)
(b)
(c)
| Final Answer:
|
| (a)
|
| (b)
|
| (c)
|
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