Difference between revisions of "009B Sample Midterm 2, Problem 1"
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!Step 1: | !Step 1: | ||
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− | | | + | |Since our interval is <math>[1,5]</math> and we are using 4 rectangles, each rectangle has width 1. So, the left-endpoint Riemann sum is |
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− | | | + | |<math>1(f(1)+f(2)+f(3)+f(4))</math>. |
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!Step 2: | !Step 2: | ||
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− | | | + | |Thus, the left-endpoint Riemann sum is |
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− | | | + | |<math>1(f(1)+f(2)+f(3)+f(4))=\bigg(1+\frac{1}{4}+\frac{1}{9}+{1}{16}\bigg)=\frac{205}{144}</math>. |
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!Final Answer: | !Final Answer: | ||
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− | |'''(a)''' | + | |'''(a)''' <math>\frac{205}{144}</math> |
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|'''(b)''' | |'''(b)''' | ||
|} | |} | ||
[[009B_Sample_Midterm_2|'''<u>Return to Sample Exam</u>''']] | [[009B_Sample_Midterm_2|'''<u>Return to Sample Exam</u>''']] |
Revision as of 14:22, 31 January 2016
Consider the region bounded by and the -axis.
- a) Use four rectangles and a Riemann sum to approximate the area of the region . Sketch the region and the rectangles and indicate your rectangles overestimate or underestimate the area of .
- b) Find an expression for the area of the region as a limit. Do not evaluate the limit.
Foundations: |
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Link to Riemann sums page |
Solution:
(a)
Step 1: |
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Since our interval is and we are using 4 rectangles, each rectangle has width 1. So, the left-endpoint Riemann sum is |
. |
Step 2: |
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Thus, the left-endpoint Riemann sum is |
. |
(b)
Step 1: |
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Step 2: |
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Final Answer: |
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(a) |
(b) |