Difference between revisions of "009B Sample Midterm 1, Problem 3"

From Grad Wiki
Jump to navigation Jump to search
Line 17: Line 17:
 
!Step 1:    
 
!Step 1:    
 
|-
 
|-
|
+
|We proceed using integration by parts. Let <math>u=x^2</math> and <math>dv=e^xdx</math>. Then, <math>du=2xdx</math> and <math>v=e^x</math>.
 +
|-
 +
|Therefore, we have
 
|-
 
|-
|
+
|<math>\int x^2 e^xdx=x^2e^x-\int 2xdx</math>
 
|}
 
|}
  
Line 25: Line 27:
 
!Step 2: &nbsp;
 
!Step 2: &nbsp;
 
|-
 
|-
|
+
|Now, we need to use integration by parts again. Let <math>u=2x</math> and <math>dv=e^xdx</math>. Then, <math>du=2dx</math> and <math>v=e^x</math>.
 +
|-
 +
|Therefore, we have
 
|-
 
|-
|
+
|<math>\int x^2 e^xdx=x^2e^x-\bigg(2xe^x-\int 2e^xdx\bigg)=x^2e^x-2xe^x+2e^x+C</math>
 
|}
 
|}
  
Line 58: Line 62:
 
!Final Answer: &nbsp;  
 
!Final Answer: &nbsp;  
 
|-
 
|-
|'''(a)'''  
+
|'''(a)''' <math>x^2e^x-2xe^x+2e^x+C</math>
 
|-
 
|-
 
|'''(b)'''  
 
|'''(b)'''  
 
|}
 
|}
 
[[009B_Sample_Midterm_1|'''<u>Return to Sample Exam</u>''']]
 
[[009B_Sample_Midterm_1|'''<u>Return to Sample Exam</u>''']]

Revision as of 12:08, 31 January 2016

Evaluate the indefinite and definite integrals.

a)
b)


Foundations:  
Review integration by parts

Solution:

(a)

Step 1:  
We proceed using integration by parts. Let and . Then, and .
Therefore, we have
Step 2:  
Now, we need to use integration by parts again. Let and . Then, and .
Therefore, we have

(b)

Step 1:  
Step 2:  
Final Answer:  
(a)
(b)

Return to Sample Exam