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	<title>Challenge Problem 2 Solution - Revision history</title>
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	<updated>2026-05-20T07:50:52Z</updated>
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	<entry>
		<id>https://gradwiki.math.ucr.edu/index.php?title=Challenge_Problem_2_Solution&amp;diff=658&amp;oldid=prev</id>
		<title>Ryan Moruzzi: Created page with &quot;==Challenge Problem 2 Solution==   In order for no cats to collide, all four cats must walk in the same direction.  Thus, all four cats must walk clockwise OR all four cats mu...&quot;</title>
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		<updated>2015-05-02T17:37:10Z</updated>

		<summary type="html">&lt;p&gt;Created page with &amp;quot;==Challenge Problem 2 Solution==   In order for no cats to collide, all four cats must walk in the same direction.  Thus, all four cats must walk clockwise OR all four cats mu...&amp;quot;&lt;/p&gt;
&lt;p&gt;&lt;b&gt;New page&lt;/b&gt;&lt;/p&gt;&lt;div&gt;==Challenge Problem 2 Solution==&lt;br /&gt;
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In order for no cats to collide, all four cats must walk in the same direction.  Thus, all four cats must walk clockwise OR all four cats must walk counterclockwise.  This means &amp;lt;math&amp;gt;P(&amp;lt;/math&amp;gt;no cats collide&amp;lt;math&amp;gt;) = P(&amp;lt;/math&amp;gt;all cats go clockwise&amp;lt;math&amp;gt;) + P(&amp;lt;/math&amp;gt;all cats go counterclockwise&amp;lt;math&amp;gt;)&amp;lt;/math&amp;gt;.  &lt;br /&gt;
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The probability a cat chooses clockwise or counterclockwise is &amp;lt;math&amp;gt;1/2&amp;lt;/math&amp;gt;.  So the probability all four cats choose clockwise or counterclockwise is &amp;lt;math&amp;gt;(1/2)*(1/2)*(1/2)*(1/2)&amp;lt;/math&amp;gt;.  &lt;br /&gt;
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Therefore, &amp;lt;math&amp;gt;P(&amp;lt;/math&amp;gt;no cats collide&amp;lt;math&amp;gt;) = (1/2)*(1/2)*(1/2)*(1/2) + (1/2)*(1/2)*(1/2)*(1/2) = 1/16 + 1/16 = 1/8.&amp;lt;/math&amp;gt;&lt;/div&gt;</summary>
		<author><name>Ryan Moruzzi</name></author>
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