8A F11 Q8 - Revision history

Matt Lee at 20:54, 13 May 2015

2015-05-13T20:54:10Z

2015-04-14T06:56:28Z

2015-04-08T15:22:53Z

2015-04-06T22:32:02Z

2015-04-06T22:31:48Z

2015-04-06T22:30:58Z

2015-04-03T18:09:35Z

2015-04-03T16:14:16Z

2015-04-02T23:53:23Z

2015-03-23T17:15:15Z

@@ Line 61: / Line 61: @@
 |- style = "text-align:center"
+|
-<math >\begin{array}{rcl}
+<math>\begin{array}{rcl}
-A_{15} &= &27 + (-4)(15 - 1)\\
+A_{15} &=& 27 + (-4)(15 - 1)\\
-& =& 27 - 56\\
+& = &27 - 56\\
 & =& -39
 \end{array}</math>

@@ Line 67: / Line 67: @@
 \end{array}</math>
 |}
 {| class="mw-collapsible mw-collapsed" style = "text-align:left;"

← Older revision		Revision as of 15:22, 8 April 2015
Line 68:		Line 68:
	\|}		\|}

		+
		+	{\| class="mw-collapsible mw-collapsed" style = "text-align:left;"
		+	! Final Answer:
		+	\|-
		+	\|<math>S_{10} = -90, A_{15} = -39</math>
		+	\|}
	[[8AF11Final\|<u>'''Return to Sample Exam</u>''']]		[[8AF11Final\|<u>'''Return to Sample Exam</u>''']]

← Older revision		Revision as of 22:32, 6 April 2015
Line 67:		Line 67:
	\end{array}</math>		\end{array}</math>
	\|}		\|}
		+
		+	[[8AF11Final\|<u>'''Return to Sample Exam</u>''']]

@@ Line 45: / Line 45: @@
 \end{array}</math>
 |-
-and
+|and
 |-style = "text-align:center"
+|

@@ Line 36: / Line 36: @@
 ! Step 3:
 |-
-|Now we have d, and we can use the same formula for <math>A_n</math> to get <math>A_{10}</math> and <math>A_{15}</math>. Using these formulas with the appropriate values will yield <math>A_{15} = 27 + (-4)(15 - 1) = 27 - 56 = -39</math>, and <math>A_{10} = 27 + (-4)(10 - 1) = 27 -36 = -9</math>
+|Now we have d, and we can use the same formula for <math>A_n</math> to get <math>A_{10}</math> and <math>A_{15}</math>. Using these formulas with the appropriate values will yield
 |}

@@ Line 43: / Line 43: @@
 |-
 |Since we found <math>A_{15}</math> in the last step, and we found the necessary pieces, we find <math>S_{10}</math> by using the formula <math>S_{10} = \frac{10}{2}(27 + -9) = 5 (-18) = -90</math>
 |}

@@ Line 42: / Line 42: @@
 ! Step 4:
 |-
-|Since we found <math>A_{15}</math> in the last step, and we found the necessary pieces, we can find <math>S_{10}</math> by using the formula <math>S_{10} = \frac{10}{2}(27 + -9) = 5 (-18) = -90</math>
+|Since we found <math>A_{15}</math> in the last step, and we found the necessary pieces, we find <math>S_{10}</math> by using the formula <math>S_{10} = \frac{10}{2}(27 + -9) = 5 (-18) = -90</math>
 |}