8A F11 Q7 - Revision history

Matt Lee at 15:21, 8 April 2015

2015-04-08T15:21:23Z

Matt Lee at 22:26, 6 April 2015

2015-04-06T22:26:40Z

Matt Lee: Created page with "'''Question:''' Solve $2\vert 3x-4\vert -7 = 7$ {| class="mw-collapsible mw-collapsed" style = "text-align:left;" !Foundations |- |1) How..."

2015-03-23T03:10:36Z

Created page with "'''Question:''' Solve <math>2\vert 3x-4\vert -7 = 7</math> {| class="mw-collapsible mw-collapsed" style = "text-align:left;" !Foundations |- |1) How..."

New page

'''Question:''' Solve      <math>2\vert 3x-4\vert -7 = 7</math>

{| class="mw-collapsible mw-collapsed" style = "text-align:left;"
!Foundations
|-
|1) How do we get to the first key step in solving any function involving absolute value equations?
|-
|2) How do we solve absolute value equations?
|-
|Answer:
|-
|1) We isolate everything inside of the absolute value signs.
|-
|2) We create two equations based on whether the expression inside the absolute value is positive or negative.
|-
|Then we solve both equations.
|}

Solution:

{| class="mw-collapsible mw-collapsed" style = "text-align:left;"
! Step 1:
|-
|Isolate the absolute values. First by adding 7 to both sides, then dividing both sides by 2.
|-
|This leads to <math>\vert 3x - 4\vert = 7.</math>
|}

{| class="mw-collapsible mw-collapsed" style = "text-align:left;"
! Step 2:
|-
|Now we create two equations: <math>3x - 4 = 7</math> and <math>3x - 4 = -7</math>.
|}

{| class="mw-collapsible mw-collapsed" style = "text-align:left;"
! Step 3:
|-
|Now we solve both equations. The first leads to the solution <math>x = \frac{11}{3}</math>. The second leads to <math>x = -1</math>
|}

← Older revision		Revision as of 15:21, 8 April 2015
Line 39:		Line 39:
	\|}		\|}

		+	{\| class="mw-collapsible mw-collapsed" style = "text-align:left;"
		+	! Final Solution:
		+	\|-
		+	\|<math>x = \frac{11}{3}, -1</math>
		+	\|}
	[[8AF11Final\|<u>'''Return to Sample Exam</u>''']]		[[8AF11Final\|<u>'''Return to Sample Exam</u>''']]

@@ Line 1: / Line 1: @@
-'''Question:''' Solve &nbsp;&nbsp;&nbsp;&nbsp; <math>2\vert 3x-4\vert -7 = 7</math>
+'''Question:''' Solve <math>2\vert 3x-4\vert -7 = 7</math>
 {| class="mw-collapsible mw-collapsed" style = "text-align:left;"
@@ Line 38: / Line 38: @@
 |Now we solve both equations. The first leads to the solution <math>x = \frac{11}{3}</math>. The second leads to <math>x = -1</math>
 |}

8A F11 Q7 - Revision history

Matt Lee at 15:21, 8 April 2015

Matt Lee at 22:26, 6 April 2015

Matt Lee: Created page with "'''Question:''' Solve 2\vert 3x-4\vert -7 = 7 {| class="mw-collapsible mw-collapsed" style = "text-align:left;" !Foundations |- |1) How..."

Matt Lee: Created page with "'''Question:''' Solve $2\vert 3x-4\vert -7 = 7$ {| class="mw-collapsible mw-collapsed" style = "text-align:left;" !Foundations |- |1) How..."